((t^2-25)/(5t))(35/(7t-35))

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Solution for ((t^2-25)/(5t))(35/(7t-35)) equation: 


D( t )

5*t = 0

7*t-35 = 0

5*t = 0

5*t = 0

5*t = 0 // : 5

t = 0

7*t-35 = 0

7*t-35 = 0

7*t-35 = 0 // + 35

7*t = 35 // : 7

t = 35/7

t = 5

t in (-oo:0) U (0:5) U (5:+oo)

((t^2-25)/(5*t))*(35/(7*t-35)) = 0

(35*(t^2-25))/(5*t*(7*t-35)) = 0

1*t^2 = 25 // : 1

t^2 = 25

t^2 = 25 // ^ 1/2

abs(t) = 5

t = 5 or t = -5

t in { 5} 

t = -5

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